James's Math Hub
Algebra & Geometry

Lesson 3 / 5 · 10 min read

Pythagorean Theorem & Right Triangles

Find missing sides and learn the basic trig ratios.

The Pythagorean theorem

For a right triangle with legs aa and bb and hypotenuse cc (the side opposite the right angle):

a2+b2=c2a^2 + b^2 = c^2

Example. Legs 33 and 44. Then c2=9+16=25c^2 = 9 + 16 = 25, so c=5c = 5. This is the famous 3-4-5 triangle.

Example — finding a leg. If c=13c = 13 and a=5a = 5, then b2=16925=144b^2 = 169 - 25 = 144, so b=12b = 12. (The 5-12-13 triangle.)

Common right triangles to memorize

Sides
3, 4, 5
5, 12, 13
8, 15, 17
7, 24, 25

Any multiple works too — a 6-8-10 triangle is just 3-4-5 scaled by 2.

Basic trig ratios — SOH CAH TOA

For a right triangle with one of the acute angles labeled θ\theta:

  • Sine: sinθ=oppositehypotenuse\sin \theta = \dfrac{\text{opposite}}{\text{hypotenuse}} (SOH)
  • Cosine: cosθ=adjacenthypotenuse\cos \theta = \dfrac{\text{adjacent}}{\text{hypotenuse}} (CAH)
  • Tangent: tanθ=oppositeadjacent\tan \theta = \dfrac{\text{opposite}}{\text{adjacent}} (TOA)

The opposite side is across from θ\theta. The adjacent side is next to θ\theta (and not the hypotenuse).

Example. In a right triangle, the side opposite θ\theta is 33 and the hypotenuse is 55. Then:

sinθ=35=0.6\sin \theta = \frac{3}{5} = 0.6

Special right triangles

45-45-90: legs equal, hypotenuse is 2\sqrt{2} times a leg. Sides: 1,1,21, 1, \sqrt{2}.

30-60-90: sides in ratio 1:3:21 : \sqrt{3} : 2. The side opposite 3030^\circ is shortest; opposite 6060^\circ is 3\sqrt{3} times that; the hypotenuse is twice the shortest.

Key takeaways

  • a2+b2=c2a^2 + b^2 = c^2 only works for right triangles, with cc as the hypotenuse.
  • SOH CAH TOA defines the three basic trig ratios.
  • Recognize 3-4-5 and 5-12-13 on sight to save time.